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The potential difference across the ends of a conductor is(50±3)Vand the current through it is(5±0.1)A. The percentage error in the measurement of resistance of the conductor is(a) 2(b) 4(e) 8(d) 6

Question

The potential difference across the ends of a conductor is(50±3)Vand the current through it is(5±0.1)A. The percentage error in the measurement of resistance of the conductor is(a) 2(b) 4(e) 8(d) 6

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Solution

To find the percentage error in the measurement of resistance, we can use the formula:

Percentage error = (Error / Measurement) * 100

First, let's calculate the error in the potential difference and current measurements:

Error in potential difference = ±3V Error in current = ±0.1A

Now, let's calculate the resistance using Ohm's Law:

Resistance = Potential difference / Current

Using the given values:

Resistance = (50 ± 3)V / (5 ± 0.1)A

To find the maximum and minimum values of resistance, we will use the maximum and minimum values of potential difference and current:

Maximum resistance = (50 + 3)V / (5 - 0.1)A Minimum resistance = (50 - 3)V / (5 + 0.1)A

Now, let's calculate the percentage error in the measurement of resistance using the formula mentioned earlier:

Percentage error = (Error in resistance / Resistance) * 100

For the maximum value of resistance:

Error in resistance = Maximum resistance - Resistance Percentage error = (Error in resistance / Resistance) * 100

Similarly, for the minimum value of resistance:

Error in resistance = Resistance - Minimum resistance Percentage error = (Error in resistance / Resistance) * 100

Now, let's calculate the percentage error for both the maximum and minimum values of resistance and compare them to find the correct option.

This problem has been solved

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