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Two resistance are given as R1=(10±0.5) Ω and R2=(15±0.5) Ω. The percentage error in the measurement of equivalent resistance when they are connected in parallel is

Question

Two resistance are given as R1=(10±0.5) Ω and R2=(15±0.5) Ω. The percentage error in the measurement of equivalent resistance when they are connected in parallel is

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Solution

The equivalent resistance (R) when two resistors are connected in parallel is given by the formula:

1/R = 1/R1 + 1/R2

First, calculate the equivalent resistance using the given values of R1 and R2:

1/R = 1/10 + 1/15 1/R = 0.1 + 0.0667 1/R = 0.1667 R = 6 Ω

Next, calculate the percentage error in the measurement of each resistor. The percentage error is given by the formula:

Percentage error = (Absolute error / Measured value) * 100%

For R1: Percentage error = (0.5 / 10) * 100% = 5%

For R2: Percentage error = (0.5 / 15) * 100% = 3.33%

When resistors are connected in parallel, the percentage errors are added together:

Total percentage error = Percentage error of R1 + Percentage error of R2 Total percentage error = 5% + 3.33% = 8.33%

So, the percentage error in the measurement of the equivalent resistance when the resistors are connected in parallel is 8.33%.

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