The effective resistance is Ω, when two wires are joined in parallel. When one of the wire breaks, the effective resistance is 2 ohms. The resistance of the broken wire was :
Question
The effective resistance is Ω, when two wires are joined in parallel. When one of the wire breaks, the effective resistance is 2 ohms. The resistance of the broken wire was :
Solution
The problem seems to be missing some information, specifically the resistance when the two wires are joined in parallel. However, I can still explain the process of how to solve it.
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Let's assume the resistance when the two wires are joined in parallel is R1 ohms, and the resistance of the unbroken wire is R2 ohms. The resistance of the broken wire is what we're trying to find, let's call it X ohms.
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When two resistors are in parallel, the total or effective resistance (R1) can be found using the formula: 1/R1 = 1/R2 + 1/X.
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When one of the wires breaks, the effective resistance is just the resistance of the unbroken wire, which is given as 2 ohms. So, R2 = 2 ohms.
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Substitute R2 = 2 ohms into the formula from step 2 to get: 1/R1 = 1/2 + 1/X.
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Solve this equation for X to find the resistance of the broken wire.
Without the value for R1, we can't complete the calculation. Please provide the resistance when the two wires are joined in parallel.
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