A = 2 4 1 6 4 8 3 14(a) Find the reduced row echelon form of A
Question
A = 2 4 1 6 4 8 3 14(a) Find the reduced row echelon form of A
Solution
The given matrix A is:
2 4 1 6 4 8 3 14
To find the reduced row echelon form (RREF), we need to perform a series of row operations. The goal is to create a leading 1 in each row and use it to make the elements below and above it 0.
Step 1: Divide the first row by 2 to get a leading 1:
1 2 0.5 3 2 4 1.5 7
Step 2: Subtract 2 times the first row from the second row to make the second element in the second row 0:
1 2 0.5 3 2 4 1.5 7 0 0 -1 -6 -4 -8 -3 -14
Step 3: Multiply the second row by -1 to get a leading 1:
1 2 0.5 3 2 4 1.5 7 0 0 1 6 4 8 3 14
Step 4: Subtract 0.5 times the second row from the first row to make the third element in the first row 0:
1 2 0 -0.5 -0.5 -0.5 -0.5 -0.5 0 0 1 6 4 8 3 14
This is the reduced row echelon form of the matrix A.
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