If a matrix is in reduced row echelon form, then it is also in row echelon form:Question 2Answera.May beb.None of thesec.Falsed.True

Determine whether the following matrices are in row echelon form (but not reduced row echelon form), reduced row echelon form, or not in row echelon form. (1)[1, 0,0],[0,1,0],[0,0,0](2)[-4,8,4,-7,-2], [0,-6,1,1,1], [0,0,1,0,3],[0,0,0,1,0](3)[7,0,1],[0,6,0](4)[1,0,0,4],[0,0,0,0],[0,1,0,-6]

A = 2 4 1 6 4 8 3 14(a) Find the reduced row echelon form of A

is this matrix in reduced row echelon form \[ \begin{bmatrix}1 & 5 & 0 & \vert & 0 \\0 & 0 & 1& \vert & 4 \\0 & 0 & 0 & \vert & 1\end{bmatrix} \]

Given the following, find the reduced row echelon form of the augmented matrix [A | b]. (Enter your answer as one augmented matrix.)A = 2 2 6 14 4 4 15 34 and b = 16 38RREF = Find the solution of Ax = b, where s and t are arbitrary real numbers. (Assume x2 = s and x4 = t. If a solution does not exist, enter DNE into any cell of each matrix.)

A𝐴 is a 5×55×5 matrix with columns given by the vectors a1,a2,a3,a4,a5𝑎1,𝑎2,𝑎3,𝑎4,𝑎5  so,A=(a1  a2  a3  a4  a5)𝐴=(𝑎1  𝑎2  𝑎3  𝑎4  𝑎5) If you need to refer to these column vectors in any answer use a1 for a1𝑎1 , a2 for a2𝑎2 etc. A𝐴  has row-reduced echelon form (RREF)U=𝑈= ⎛⎝⎜⎜⎜⎜⎜⎜1000020000010000010000010⎞⎠⎟⎟⎟⎟⎟⎟1200000100000100000100000 State the rank and nullitty of A𝐴 .rank(A)=rank(𝐴)=   nullity(A)=nullity(𝐴)=     Find a basis for the kernel or nullspace of  A𝐴 ,  ker(A)ker(𝐴) . Your answer must be a set of vectors, that is a sequence of vectors separated by commas enclosed in curly brackets { }.  Vectors can either be entered either using Maple notaation, for example,   < 3, 7 >  for the vector (37)(37) or in terms of the vectors   a1,a2,a3,a4,a5𝑎1,𝑎2,𝑎3,𝑎4,𝑎5  written as  a1, a2, a3, a4, a5.The syntax for typical answers is one of the following two forms: { <1,2,3>, <4,5,6>, <1,1,1> }  or  { a2, a3, a4 } Basis for  ker(A)=ker(𝐴)=