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A sinusoidal wave traveling in the +𝑥 direction (to the right) has an amplitude of 15.0 cm, a wavelength of 10.0 cm and a frequency of 20.0 Hz. At t = 0, a particle at x = 0 has a displacement of 15.0 cm.(a) Write an expression for the wave function, y(x, t).20:39

Question

A sinusoidal wave traveling in the +𝑥 direction (to the right) has an amplitude of 15.0 cm, a wavelength of 10.0 cm and a frequency of 20.0 Hz. At t = 0, a particle at x = 0 has a displacement of 15.0 cm.(a) Write an expression for the wave function, y(x, t).20:39

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Solution

The wave function for a sinusoidal wave traveling in the +x direction is given by the equation:

y(x, t) = A sin(kx - wt + φ)

where:

  • A is the amplitude of the wave,
  • k is the wave number, which is equal to 2π/λ (λ is the wavelength),
  • w is the angular frequency, which is equal to 2πf (f is the frequency),
  • φ is the phase constant.

Given that the amplitude A = 15.0 cm, the wavelength λ = 10.0 cm, and the frequency f = 20.0 Hz, we can calculate k and w as follows:

k = 2π/λ = 2π/10.0 cm = 0.2π cm^-1 w = 2πf = 2π*20.0 Hz = 40π rad/s

At t = 0, a particle at x = 0 has a displacement of 15.0 cm, which is the maximum displacement. This means that the phase constant φ = 0.

Therefore, the wave function is:

y(x, t) = 15.0 cm sin(0.2πx - 40πt)

This problem has been solved

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