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A wave, travelling along the x axis, is described by the equationy = 0.14 sin (5.7π t − 0.37π x) where t is in seconds, and x is in metres. Determine thewave’s frequency

Question

A wave, travelling along the x axis, is described by the equationy = 0.14 sin (5.7π t − 0.37π x) where t is in seconds, and x is in metres. Determine thewave’s frequency

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Solution

The frequency of a wave is determined by the coefficient of the time variable (t) in the wave equation. In this case, the wave equation is given as y = 0.14 sin (5.7π t − 0.37π x).

The coefficient of t is 5.7π. This value represents the angular frequency of the wave, not the frequency. The angular frequency (ω) and the frequency (f) are related by the equation ω = 2πf.

So, to find the frequency, we can rearrange this equation to solve for f:

f = ω / 2π

Substituting the given angular frequency into this equation gives:

f = 5.7π / 2π

Solving this equation gives the frequency of the wave as f = 5.7 / 2 = 2.85 Hz.

This problem has been solved

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