Suppose a jar contains 20 red marbles and 37 blue marbles. If 2 marbles are randomly chosen from the jar at the same time, find the probability that both marbles are red. Round your answer to four decimal places.
Question
Suppose a jar contains 20 red marbles and 37 blue marbles. If 2 marbles are randomly chosen from the jar at the same time, find the probability that both marbles are red. Round your answer to four decimal places.
Solution
Sure, here's how you can solve this problem:
Step 1: Calculate the total number of marbles in the jar. This is the sum of the red and blue marbles, which is 20 (red) + 37 (blue) = 57 marbles.
Step 2: Calculate the probability of drawing a red marble on the first draw. This is the number of red marbles divided by the total number of marbles, which is 20/57.
Step 3: If a red marble is drawn first, there are now 19 red marbles left and 56 total marbles left. So, the probability of drawing a red marble on the second draw is 19/56.
Step 4: The probability of both events happening (drawing a red marble twice in a row) is the product of the probabilities of each event. So, the probability of drawing two red marbles in a row is (20/57) * (19/56) = 0.0606.
So, the probability that both marbles drawn are red, rounded to four decimal places, is 0.0606.
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