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Suppose a jar contains 20 red marbles and 37 blue marbles. If 2 marbles are randomly chosen from the jar at the same time, find the probability that both marbles are red. Round your answer to four decimal places.

Question

Suppose a jar contains 20 red marbles and 37 blue marbles. If 2 marbles are randomly chosen from the jar at the same time, find the probability that both marbles are red. Round your answer to four decimal places.

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Solution

Sure, here's how you can solve this problem:

Step 1: Calculate the total number of marbles in the jar. This is the sum of the red and blue marbles, which is 20 (red) + 37 (blue) = 57 marbles.

Step 2: Calculate the probability of drawing a red marble on the first draw. This is the number of red marbles divided by the total number of marbles, which is 20/57.

Step 3: If a red marble is drawn first, there are now 19 red marbles left and 56 total marbles left. So, the probability of drawing a red marble on the second draw is 19/56.

Step 4: The probability of both events happening (drawing a red marble twice in a row) is the product of the probabilities of each event. So, the probability of drawing two red marbles in a row is (20/57) * (19/56) = 0.0606.

So, the probability that both marbles drawn are red, rounded to four decimal places, is 0.0606.

This problem has been solved

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