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A jar contains 12 red marbles numbered 1 to 12 and 8 blue marbles numbered 1 to 8. A marble is drawn at random from the jar. Round your answer to four decimal places. Find the probability that the marble is red: marble is odd-numbered: marble is red or blue:

Question

A jar contains 12 red marbles numbered 1 to 12 and 8 blue marbles numbered 1 to 8. A marble is drawn at random from the jar. Round your answer to four decimal places. Find the probability that the

marble is red:

marble is odd-numbered:

marble is red or blue:

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Solution

Sure, let's solve these one by one:

  1. The probability that the marble is red:

There are 12 red marbles and a total of 20 marbles (12 red + 8 blue). So, the probability that the marble is red is the number of red marbles divided by the total number of marbles.

Probability = Number of red marbles / Total number of marbles = 12 / 20 = 0.6000

  1. The probability that the marble is odd-numbered:

There are 10 odd-numbered marbles (1, 3, 5, 7, 9, 11 from the red marbles and 1, 3, 5, 7 from the blue marbles). So, the probability that the marble is odd-numbered is the number of odd-numbered marbles divided by the total number of marbles.

Probability = Number of odd-numbered marbles / Total number of marbles = 10 / 20 = 0.5000

  1. The probability that the marble is red or blue:

Since all the marbles are either red or blue, the probability that the marble is red or blue is 1 or 100%.

Probability = Total number of marbles / Total number of marbles = 20 / 20 = 1.0000

This problem has been solved

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