Two charges are separated by a distance, d and exert mutual attractive forces of F on each other. If both charges are doubled but kept the same distance apart, what are the new mutual forces?*1 pointF/2F/42F4F
Question
Two charges are separated by a distance, d and exert mutual attractive forces of F on each other. If both charges are doubled but kept the same distance apart, what are the new mutual forces?*1 pointF/2F/42F4F
Solution
The force between two charges is given by Coulomb's Law, which states that the force (F) between two charges (q1 and q2) separated by a distance (d) is given by:
F = k * q1 * q2 / d^2
where k is Coulomb's constant.
If both charges are doubled, the equation becomes:
F' = k * 2q1 * 2q2 / d^2 = 4 * k * q1 * q2 / d^2 = 4F
So, the new mutual forces will be 4F.
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