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ect the correct answerA boy walking at a speed of 20kmph reaches his school 15min late. Next time at a speed of 25kmph reaches his school 10m early find the usual time to reach the school?Options120min110min150min144min

Question

ect the correct answerA boy walking at a speed of 20kmph reaches his school 15min late. Next time at a speed of 25kmph reaches his school 10m early find the usual time to reach the school?Options120min110min150min144min

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Solution

Let's solve this step by step:

  1. First, we need to convert the speed from km/h to km/min because the time is given in minutes. So, 20 km/h = 20/60 km/min = 1/3 km/min and 25 km/h = 25/60 km/min = 5/12 km/min.

  2. Let's denote the distance to school as D (in km) and the usual time to reach the school as T (in minutes).

  3. From the first condition (the boy is 15 min late when walking at a speed of 1/3 km/min), we can write the equation: D = (T+15) * (1/3).

  4. From the second condition (the boy is 10 min early when walking at a speed of 5/12 km/min), we can write the equation: D = (T-10) * (5/12).

  5. Now we have a system of two equations with two variables (D and T) which we can solve. Setting the two equations equal to each other gives us: (T+15) * (1/3) = (T-10) * (5/12).

  6. Solving this equation for T gives us: T = 120 minutes.

So, the usual time to reach the school is 120 minutes.

This problem has been solved

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