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Select the correct answerA man starts from his house and travelling at 30 km/h, he reaches his office late by 10 minutes, and travelling at 24 km/h, he reaches his office late by 18 minutes. The distance (in km) from his house to his office is?Options20121816

Question

Select the correct answerA man starts from his house and travelling at 30 km/h, he reaches his office late by 10 minutes, and travelling at 24 km/h, he reaches his office late by 18 minutes. The distance (in km) from his house to his office is?Options20121816

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Solution

To solve this problem, we can use the concept of relative speed.

The difference in speed between the two scenarios is 6 km/h (30 km/h - 24 km/h), and the difference in time is 8 minutes (18 minutes - 10 minutes).

We can convert 8 minutes to hours, which is 8/60 = 0.1333 hours.

Since speed = distance/time, we can rearrange the formula to find distance = speed * time.

So, the distance = 6 km/h * 0.1333 hours = 0.8 km.

This is the extra distance the man travels when he is moving at a faster speed.

But we need to find the total distance from his house to his office.

We know that when he travels at 30 km/h, he is late by 10 minutes, which is 10/60 = 0.1667 hours.

So, the total distance = speed * time = 30 km/h * 0.1667 hours = 5 km.

Therefore, the distance from his house to his office is 5 km.

But this answer is not in the options. There might be a mistake in the problem or the options.

This problem has been solved

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