To solve this problem, you can use the ASCII values of the characters. Here is a step-by-step guide on how to do it in C: 1. First, you need to include the necessary libraries. In this case, you need the stdio.h library for input and output functions. ```c #include ``` 2. Then, declare the main function. ```c int main() { ``` 3. Inside the main function, declare a character variable to store the input character and an integer variable to store the shift amount. ```c char c; int n; ``` 4. Use the scanf function to get the input from the user. ```c scanf("%c %d", &c, &n); ``` 5. Now, check if the input character is a lowercase or uppercase letter. If it is, perform the shift operation. If it's not, print the character as it is. ```c if(c = 'a' && c = 'A' && c = 'a' && c = 'A' && c

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To solve this problem, you can use the ASCII values of the characters. Here is a step-by-step guide on how to do it in C: 1. First, you need to include the necessary libraries. In this case, you need the stdio.h library for input and output functions. ```c #include ``` 2. Then, declare the main function. ```c int main() { ``` 3. Inside the main function, declare a character variable to store the input character and an integer variable to store the shift amount. ```c char c; int n; ``` 4. Use the scanf function to get the input from the user. ```c scanf("%c %d", &c, &n); ``` 5. Now, check if the input character is a lowercase or uppercase letter. If it is, perform the shift operation. If it's not, print the character as it is. ```c if(c >= 'a' && c <= 'z') { c = ((c - 'a' + n) % 26) + 'a'; } else if(c >= 'A' && c <= 'Z') { c = ((c - 'A' + n) % 26) + 'A'; } printf("%c", c); ``` 6. Finally, return 0 to indicate that the program has finished successfully. ```c return 0; } ``` Here is the complete code: ```c #include int main() { char c; int n; scanf("%c %d", &c, &n); if(c >= 'a' && c <= 'z') { c = ((c - 'a' + n) % 26) + 'a'; } else if(c >= 'A' && c <= 'Z') { c = ((c - 'A' + n) % 26) + 'A'; } printf("%c", c); return 0; } ``` This program works by shifting the ASCII value of the input character by the specified amount. The modulo operation ensures that the shift wraps around the alphabet.

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To solve this problem, you can use the ASCII values of the characters. Here is a step-by-step guide on how to do it in C: 1. First, you need to include the necessary libraries. In this case, you need the stdio.h library for input and output functions. ```c #include ``` 2. Then, declare the main function. ```c int main() { ``` 3. Inside the main function, declare a character variable to store the input character and an integer variable to store the shift amount. ```c char c; int n; ``` 4. Use the scanf function to get the input from the user. ```c scanf("%c %d", &c, &n); ``` 5. Now, check if the input character is a lowercase or uppercase letter. If it is, perform the shift operation. If it's not, print the character as it is. ```c if(c >= 'a' && c <= 'z') { c = ((c - 'a' + n) % 26) + 'a'; } else if(c >= 'A' && c <= 'Z') { c = ((c - 'A' + n) % 26) + 'A'; } printf("%c", c); ``` 6. Finally, return 0 to indicate that the program has finished successfully. ```c return 0; } ``` Here is the complete code: ```c #include int main() { char c; int n; scanf("%c %d", &c, &n); if(c >= 'a' && c <= 'z') { c = ((c - 'a' + n) % 26) + 'a'; } else if(c >= 'A' && c <= 'Z') { c = ((c - 'A' + n) % 26) + 'A'; } printf("%c", c); return 0; } ``` This program works by shifting the ASCII value of the input character by the specified amount. The modulo operation ensures that the shift wraps around the alphabet.

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