For a memory whose memory address uses the first 9 address lines. If all the 16 lines have to be implemented for addressing,. What time of internal decoder must be used for the chip select.Question 2Select one:a.4-32b.4-16c.6-64d.8-256

The question is asking about the type of internal decoder that must be used for the chip select in a memory system.

The memory address uses the first 9 address lines. This means that there are 2^9 = 512 different addresses that can be accessed.

If all the 16 lines have to be implemented for addressing, this means that there are 2^16 = 65,536 different addresses that can be accessed.

The difference between these two numbers is the number of addresses that the internal decoder must be able to handle. This is 65,536 - 512 = 65,024.

The internal decoder must therefore be able to handle 65,024 different addresses.

Looking at the options given:

a. 4-32 decoder can handle 32 different addresses b. 4-16 decoder can handle 16 different addresses c. 6-64 decoder can handle 64 different addresses d. 8-256 decoder can handle 256 different addresses

None of these options can handle 65,024 different addresses.

There seems to be a misunderstanding in the question or the options provided. The decoder that can handle 65,024 different addresses would be a 16-65536 decoder.

The question is asking about the type of internal decoder that must be used for the chip select in a memory system.

The memory address uses the first 9 address lines. This means that there are 2^9 = 512 different addresses that can be accessed.

If all the 16 lines have to be implemented for addressing, this means that there are 2^16 = 65536 different addresses that can be accessed.

The difference between these two numbers is the number of addresses that the chip select must be able to handle. This is 65536 - 512 = 65024.

The internal decoder must be able to handle this number of addresses. Looking at the options, the 6-64 decoder can handle 64 different addresses, the 4-16 decoder can handle 16 different addresses, the 4-32 decoder can handle 32 different addresses, and the 8-256 decoder can handle 256 different addresses.

None of these options can handle 65024 different addresses. Therefore, none of the options are correct.

However, if the question is asking about the additional lines needed for the chip select, then the answer would be 16 - 9 = 7. This means that a 7-128 decoder would be needed, but this option is not given in the question.

The question is asking about the type of internal decoder that must be used for the chip select in a memory system.

The memory address uses the first 9 address lines. This means that there are 2^9 = 512 unique addresses that can be generated with these 9 lines.

However, all 16 lines have to be implemented for addressing. This means that there are 2^16 = 65,536 unique addresses that can be generated with these 16 lines.

The difference between the number of addresses that can be generated with 16 lines and the number of addresses that can be generated with 9 lines is 65,536 - 512 = 65,024.

This means that the internal decoder must be able to select from 65,024 different addresses.

The closest option that can handle this number of addresses is a 6-64 decoder. However, a 6-64 decoder can only select from 64 different addresses.

Therefore, the correct answer is d. 8-256. An 8-256 decoder can select from 256 different addresses, which is more than enough to handle the 65,024 addresses that need to be selected.