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Find the equivalent resistance between points A and B of the network shown below.a) 6 Ωb) 7 Ωc) 4 Ωd) 10 Ω[1 mark]

Question

Find the equivalent resistance between points A and B of the network shown below.a) 6 Ωb) 7 Ωc) 4 Ωd) 10 Ω[1 mark]

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Solution

To find the equivalent resistance between points A and B of the network shown, we can use the concept of series and parallel resistors.

Step 1: Identify the resistors that are in series. In this case, the resistors R1 and R2 are in series.

Step 2: Calculate the equivalent resistance of the series resistors. The formula for calculating the equivalent resistance of two resistors in series is:

Rs = R1 + R2

Step 3: Substitute the values of R1 and R2 into the formula and calculate the equivalent resistance:

Rs = 2 Ω + 4 Ω Rs = 6 Ω

Step 4: Now, we have a parallel combination of the equivalent resistance Rs and the resistor R3. To calculate the equivalent resistance of these two resistors in parallel, we use the formula:

Rp = (Rs * R3) / (Rs + R3)

Step 5: Substitute the values of Rs and R3 into the formula and calculate the equivalent resistance:

Rp = (6 Ω * 4 Ω) / (6 Ω + 4 Ω) Rp = 24 Ω / 10 Ω Rp = 2.4 Ω

Therefore, the equivalent resistance between points A and B of the network is 2.4 Ω.

This problem has been solved

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