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A wire of resistance R is bent in the form of a circular loop as shown in the figure. The equivalent resistance between the points A and B is

Question

A wire of resistance R is bent in the form of a circular loop as shown in the figure. The equivalent resistance between the points A and B is

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Solution

The question seems to be incomplete as there is no figure provided. However, assuming that the wire is bent into a perfect circle and points A and B are diametrically opposite each other, the wire is effectively split into two equal halves.

Each half of the wire would have a resistance of R/2 (since resistance is directly proportional to the length of the wire).

Since these two halves are connected in parallel (from A to B), the equivalent resistance (Re) can be calculated using the formula for resistors in parallel:

1/Re = 1/(R/2) + 1/(R/2) = 2/R + 2/R = 4/R

Therefore, Re = R/4.

So, the equivalent resistance between points A and B in this scenario would be R/4.

This problem has been solved

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