The freezing point depression (ΔTf) is calculated using the formula:

ΔTf = Kf * m * i

where:
- Kf is the cryoscopic constant of the solvent (for water, it's 1.86 °C kg/mol)
- m is the molality of the solution (moles of solute/kg of solvent)
- i is the van 't Hoff factor (the number of particles the solute splits into in solution)

For calcium chloride (CaCl₂), the van 't Hoff factor is 3 because it dissociates into three ions in solution (one Ca²⁺ and two Cl⁻).

First, calculate the molality (m) of the solution:

m = moles of solute / kg of solvent
m = 0.75 mol / 0.5 kg = 1.5 mol/kg

Then, substitute the values into the formula:

ΔTf = 1.86 °C kg/mol * 1.5 mol/kg * 3 = 8.37 °C

So, the freezing point of water would be depressed by 8.37 °C. However, this option is not available in the choices given. Please check the question or the given options.

Question

The freezing point depression (ΔTf) is calculated using the formula:

ΔTf = Kf * m * i

where:
- Kf is the cryoscopic constant of the solvent (for water, it's 1.86 °C kg/mol)
- m is the molality of the solution (moles of solute/kg of solvent)
- i is the van 't Hoff factor (the number of particles the solute splits into in solution)

For calcium chloride (CaCl₂), the van 't Hoff factor is 3 because it dissociates into three ions in solution (one Ca²⁺ and two Cl⁻).

First, calculate the molality (m) of the solution:

m = moles of solute / kg of solvent
m = 0.75 mol / 0.5 kg = 1.5 mol/kg

Then, substitute the values into the formula:

ΔTf = 1.86 °C kg/mol * 1.5 mol/kg * 3 = 8.37 °C

So, the freezing point of water would be depressed by 8.37 °C. However, this option is not available in the choices given. Please check the question or the given options.

Knowee AI · Accepted Answer

The freezing point depression (ΔTf) is calculated using the formula:

ΔTf = Kf * m * i

where:
- Kf is the cryoscopic constant of the solvent (for water, it's 1.86 °C kg/mol)
- m is the molality of the solution (moles of solute/kg of solvent)
- i is the van 't Hoff factor (the number of particles the solute splits into in solution)

For calcium chloride (CaCl₂), the van 't Hoff factor is 3 because it dissociates into three ions in solution (one Ca²⁺ and two Cl⁻).

First, calculate the molality (m) of the solution:

m = moles of solute / kg of solvent
m = 0.75 mol / 0.5 kg = 1.5 mol/kg

Then, substitute the values into the formula:

ΔTf = 1.86 °C kg/mol * 1.5 mol/kg * 3 = 8.37 °C

So, the freezing point of water would be depressed by 8.37 °C. However, this option is not available in the choices given. Please check the question or the given options.

The freezing point depression constant for water is 1.86 °C kg/mol. How much would the freezing point of water be depressed when 0.75 moles of calcium chloride (CaCl₂) is dissolved in 500 grams of water?Select one:a.0.372 °Cb.0.186 °Cc.0.558 °Cd.1.860 °C

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