Calculate the solution to these simultaneous equations using the elimination method: (1)(1)4ℎ−2𝑔4h−2g==1212 (2)(2)4ℎ+𝑔4h+g==66
Question
Calculate the solution to these simultaneous equations using the elimination method: (1)(1)4ℎ−2𝑔4h−2g==1212 (2)(2)4ℎ+𝑔4h+g==66
Solution
Sure, let's solve these equations step by step:
Given equations are:
4h - 2g = 12 ----(1)
4h + g = 6 ----(2)
Step 1: Multiply equation (2) by 2 to make the coefficients of g the same in both equations. This gives us:
8h + 2g = 12 ----(3)
Step 2: Now, add equation (1) and equation (3) together:
4h - 2g + 8h + 2g = 12 + 12
This simplifies to:
12h = 24
Step 3: Divide both sides by 12 to solve for h:
h = 24 / 12 = 2
Step 4: Substitute h = 2 into equation (2) to solve for g:
4(2) + g = 6
8 + g = 6
g = 6 - 8 = -2
So, the solution to the system of equations is h = 2 and g = -2.
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