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Calculate the solution to these simultaneous equations using the elimination method: (1)(1)4ℎ−2𝑔4h−2g==1212 (2)(2)4ℎ+𝑔4h+g==66

Question

Calculate the solution to these simultaneous equations using the elimination method: (1)(1)4ℎ−2𝑔4h−2g==1212 (2)(2)4ℎ+𝑔4h+g==66

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Solution

Sure, let's solve these equations step by step:

Given equations are:

4h - 2g = 12 ----(1)

4h + g = 6 ----(2)

Step 1: Multiply equation (2) by 2 to make the coefficients of g the same in both equations. This gives us:

8h + 2g = 12 ----(3)

Step 2: Now, add equation (1) and equation (3) together:

4h - 2g + 8h + 2g = 12 + 12

This simplifies to:

12h = 24

Step 3: Divide both sides by 12 to solve for h:

h = 24 / 12 = 2

Step 4: Substitute h = 2 into equation (2) to solve for g:

4(2) + g = 6

8 + g = 6

g = 6 - 8 = -2

So, the solution to the system of equations is h = 2 and g = -2.

This problem has been solved

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