Before a collision, a 23 kg object is moving at +14 m/s. Find the impulse that acted on the object if, after the collision, it moves at the following speeds.(a) +8.0 m/s
Question
Before a collision, a 23 kg object is moving at +14 m/s. Find the impulse that acted on the object if, after the collision, it moves at the following speeds.(a) +8.0 m/s
Solution
To solve this problem, we need to use the formula for impulse, which is the change in momentum of an object. The formula for impulse (J) is:
J = Δp = m * Δv
where:
- Δp is the change in momentum,
- m is the mass of the object, and
- Δv is the change in velocity.
Given:
- m = 23 kg,
- initial velocity (v1) = +14 m/s, and
- final velocity (v2) = +8.0 m/s.
We can calculate Δv as follows:
Δv = v2 - v1 Δv = +8.0 m/s - (+14 m/s) Δv = -6 m/s
Now we can calculate the impulse:
J = m * Δv J = 23 kg * (-6 m/s) J = -138 kg*m/s
So, the impulse that acted on the object is -138 kg*m/s. The negative sign indicates that the impulse acted in the opposite direction to the initial motion of the object.
Similar Questions
Car B of mass 1200 kg is stationary. Car of mass 20 kg is travelling towards car B at 18 m/s. The cars collide and car B experiences an impulse. car A continues to move in the same direction, with a momentum of 21000 kgm/s. (i) calculate the momentum of car B immediately after the Collision. (II) Determine the average impulse experienced by car b during the Collision. (III) The cars are in contact for 0.20 s. Calculate the average resultant force experienced by car B during the collsion
A 2.00 kg toy car is moving to the right with a speed of 0.700 m/s without friction. If it experiences an impulse of -4.00 Ns, what is the object's speed and direction after the impulse occurs? 2.70 m/s to the right 5.40 m/s to the left 2.60 m/s to the right 1.30 m/s to the left
A 2.40 kg pool ball is moving to the left with a speed of 3.70 m/s without friction. If it experiences an impulse of -4.00 Ns, what is the object's speed and direction after the impulse occurs? 5.37 m/s to the left 2.03 m/s to the right 3.40 m/s to the left 11.4 m/s to the right
A 20-kg object sitting at rest is struck elastically in a head-on collision with a 12-kg object initially moving at +4.0 m/s. Find the final velocity of the 20-kg object after the collision.Select one:a.+5.0 m/sb.+13.0 m/sc.+3.0 m/sd.−1.0 m/se.−3.0 m/s
A 3000 kg truck moving with a velocity of 10 m/s hits a 1000 kg parked car. The impact causes the 1000 kg car to be set in motion at 15 m/s. Assuming that momentum is conserved during the collision, what is the velocity of the truck immediately after the collision?*1 point5 m/s10 m/s17 m/s21 m/sSubmit
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.