Convert infix expression to postfix 4*8/2+(9+8-7^2)-5*9

Sure, let's convert the infix expression to postfix. The infix expression is: 48/2+(9+8-7^2)-59

Step 1: First, we need to understand the precedence of operators. The precedence order is as follows: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

Step 2: Now, let's start converting:

Infix: 48/2+(9+8-7^2)-59 Postfix:

• Scan the infix expression from left to right.
• If the scanned character is an operand, output it.
• Else,
  • If the precedence of the scanned operator is greater than the precedence of the operator in the stack(or the stack is empty), push it.
  • Else, Pop the operator from the stack until the precedence of the scanned operator is less-equal to the precedence of the operator residing on the top of the stack. Push the scanned operator to the stack.

Let's apply these rules:

• 48/2+(9+8-7^2)-59
• 482/9+8+72^-59- (after applying the rules)
• 482/98+72^-+59- (final postfix expression)

So, the postfix expression of the given infix expression 48/2+(9+8-7^2)-59 is 482/98+72^-+59-.