At what time between 2 and 3 o'clock will the hands of a clock be together?(12 + 10/11) min past 3(10 + 10/11) min past 2(10 + 10/11) min past 3(11 + 10/11) min past 2

The hands of a clock are together at (10 + 10/11) minutes past 2.

Here's the step-by-step explanation:

1. The minute hand moves 12 times as fast as the hour hand.
2. At 2 o'clock, the hour hand is at 2 and the minute hand is at 12, so they are 10 minutes apart.
3. To find out when they will be together, we need to find out when the minute hand will have caught up to the hour hand.
4. Since the minute hand moves 12 times as fast as the hour hand, it will take (10/11) of an hour for the minute hand to catch up to the hour hand.
5. Therefore, the hands of the clock will be together at (10 + 10/11) minutes past 2.

The hands of a clock are together at (10 + 10/11) minutes past 2.

Here's the step-by-step explanation:

1. At 2 o'clock, the minute hand is at 12 and the hour hand is at 2.

2. The minute hand moves 12 times faster than the hour hand.

3. So, to find out when the hands will be together, we need to find out when the minute hand has caught up with the hour hand.

4. The hour hand moves 1/2 a minute each minute, and the minute hand moves 12 minutes each minute.

5. Therefore, the minute hand gains on the hour hand by 11.5 minutes each minute.

6. At 2 o'clock, the hour hand is 10 minutes ahead of the minute hand.

7. So, the minute hand will catch up with the hour hand in (10 / 11.5) minutes, which is approximately (10 + 10/11) minutes.

So, the hands of the clock will be together at (10 + 10/11) minutes past 2.

The hands of a clock are together at (10 + 10/11) min past 2.

Here's the step by step explanation:

1. At 2 o'clock, the minute hand is at 12 and the hour hand is at 2.

2. The minute hand moves 12 times faster than the hour hand.

3. So, to find out when the hands will be together, we need to find out when the minute hand has caught up with the hour hand.

4. The hour hand moves 1/2 a degree per minute and the minute hand moves 6 degrees per minute.

5. Therefore, the minute hand gains (6 - 1/2) = 5.5 degrees per minute on the hour hand.

6. At 2 o'clock, the hour hand is 60 degrees ahead of the minute hand (each hour on the clock represents 30 degrees, so 2 hours = 60 degrees).

7. So, the minute hand will catch up with the hour hand after (60/5.5) = 10 + 10/11 minutes.

8. Therefore, the hands of a clock will be together at (10 + 10/11) min past 2.

The hands of a clock are together 11 times in every 12 hours because the minute hand moves 12 times as fast as the hour hand. The hands are together at the start of each hour except between 11 and 12.

To find out when the hands of a clock will be together between 2 and 3 o'clock, we can use the formula:

(60 * H) / 11 minutes past H o'clock

where H is the hour.

So, substituting H = 2 into the formula, we get:

(60 * 2) / 11 = 120 / 11 = 10 + 10/11

So, the hands of a clock will be together at (10 + 10/11) minutes past 2 o'clock.

The hands of a clock will be together at (10 + 10/11) min past 2.

Here's the step-by-step explanation:

1. At 2 o'clock, the minute hand is at 12 and the hour hand is at 2.

2. The minute hand moves 12 times faster than the hour hand.

3. So, to catch up with the hour hand, the minute hand must make a 1/11th of a 12-hour rotation.

4. This takes (60/11) minutes, which is approximately (5 + 5/11) minutes.

5. But, since the hour hand is already 2/12th of the way around the clock at 2 o'clock, the minute hand has an additional (5 + 5/11) minutes to catch up.

6. Therefore, the hands of the clock will be together at (10 + 10/11) minutes past 2.

The hands of a clock are together at (10 + 10/11) minutes past 2.

Here's the step by step explanation:

1. At 2 o'clock, the minute hand is at 12 and the hour hand is at 2.

2. The minute hand moves 12 times faster than the hour hand.

3. So, to find out when the hands will be together, we need to find out when the minute hand has caught up with the hour hand.

4. The hour hand moves 1/2 a minute each minute, and the minute hand moves 12 minutes each minute.

5. So, in t minutes, the hour hand will have moved t/2 minutes, and the minute hand will have moved 12t minutes.

6. We want to find t such that 12t = t/2 + 20 (because at 2 o'clock, the hour hand is 20 minutes ahead of the minute hand).

7. Solving this equation gives t = (10 + 10/11) minutes.

So, the hands of the clock will be together at (10 + 10/11) minutes past 2.