VariablesWhat will be the status of this program upon compilation?#include <stdio.h>int main() { char j = 'a'; int i = j; int k = (int)j; int l = 75; char m = (char)l; printf("value of i = %d, k = %d\n", i, k); printf("value of l = %d, m = %c\n", l, m); getchar(); return 0;}OptionsError in compilationvalue of i = 97, k = 97value of l = 75, m = KNo Outputvalue of i = 'a', k = 97value of l = 75, m = '7
Question
VariablesWhat will be the status of this program upon compilation?#include <stdio.h>int main() { char j = 'a'; int i = j; int k = (int)j; int l = 75; char m = (char)l; printf("value of i = %d, k = %d\n", i, k); printf("value of l = %d, m = %c\n", l, m); getchar(); return 0;}OptionsError in compilationvalue of i = 97, k = 97value of l = 75, m = KNo Outputvalue of i = 'a', k = 97value of l = 75, m = '7
Solution
The status of this program upon compilation will be "value of i = 97, k = 97 value of l = 75, m = K".
Here's why:
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The character 'a' is assigned to the variable 'j'. In ASCII, 'a' corresponds to the decimal number 97.
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The value of 'j' (which is 'a' or 97 in decimal) is assigned to the integer 'i'. So, 'i' becomes 97.
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The value of 'j' is explicitly cast to an integer and assigned to 'k'. So, 'k' also becomes 97.
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The integer 75 is assigned to 'l'.
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The value of 'l' (which is 75) is explicitly cast to a character and assigned to 'm'. In ASCII, 75 corresponds to the character 'K'.
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The printf statements print the values of 'i', 'k', 'l', and 'm'. So, the output will be "value of i = 97, k = 97 value of l = 75, m = K".
Similar Questions
VariablesWhat will be the status of this program upon compilation?#include <stdio.h>/* integer variable program */int main() { int i; i = 10; printf("Value of i is %d\n", i); i = 20; printf("Value of i is %d\n", i); getchar(); return 0;}OptionsWill run successfully and display the following,Value of i is 10Value of i is 10Error in compilationWill run successfully and display the following,Value of i is 10Value of i is 20Garbage Values
VariablesWhat will be the status of this program upon compilation?#include <stdio.h>int main() { char j = 'a'; int i = j; int k = (int)j; int l = 75; char m = (char)l; printf("value of i = %d, k = %d\n", i, k); printf("value of l = %d, m = %c\n", l, m); getchar(); return 0;}OptionsError in compilationvalue of i = 97, k = 97value of l = 75, m = KNo Outputvalue of i = 'a', k = 97value of l = 75, m = '7
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What happens if we compile the following code?
ablesWhat will be the status of this program upon compilation?#include <stdio.h>int main() { char j = 'a'; int i = j; int k = (int)j; int l = 75; char m = (char)l; printf("value of i = %d, k = %d\n", i, k); printf("value of l = %d, m = %c\n", l, m); getchar(); return 0;}
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