Based on the below table, answer the following question:xP(x)30.0540.4050.3060.1570.10 Find P (4<X<7)Question 4Answera.0.40b.0.95c.0.45
Question
Based on the below table, answer the following question:xP(x)30.0540.4050.3060.1570.10 Find P (4<X<7)Question 4Answera.0.40b.0.95c.0.45
Solution 1
The probability P(4<X<7) is asking for the sum of the probabilities where X is greater than 4 and less than 7.
From the table, this includes the probabilities for X=5 and X=6.
P(5) = 0.30 and P(6) = 0.15
So, P(4<X<7) = P(5) + P(6) = 0.30 + 0.15 = 0.45
So, the answer is c. 0.45.
Solution 2
The question is asking for the probability that X is greater than 4 but less than 7.
From the table, we can see that the values for X are 3, 4, 5, 6, and 7.
The probability that X is greater than 4 but less than 7 would be the sum of the probabilities for X = 5 and X = 6.
From the table, P(X=5) = 0.30 and P(X=6) = 0.15.
So, P(4<X<7) = P(X=5) + P(X=6) = 0.30 + 0.15 = 0.45.
Therefore, the answer is c. 0.45.
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