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DIRECTIONS for questions 6 to 10: Answer these questions on the basis of the information given below.Five children – A through E – were playing a game. In each round of the game, each child independently picked a digit from 0 to 9 and after each of the five children had picked a digit, the five digits were used to form the largest possible number that can be made with the five digits (by placing them next to each other). This number is labelled as the Ceiling Number of that round. After exactly four rounds, the child who picked the leftmost digit of the highest Ceiling Number across the four rounds is declared the winner of the game. No child can pick the same number across any two rounds.The Ceiling Number of each round are 98551, 75311, 98765 and 76544, not necessarily in any particular order.It is also known thatB picked consecutive digits across the four rounds, but not necessarily in any order, and in none of the rounds did the digit that he picked become the leftmost digit of the Ceiling Number.In each round, the digit that B picked was higher than the one that D picked, while, in the second round, C and E picked the same digit.The child who was declared the winner picked the least digit of the Ceiling Number in only one round, which was the third round.For only one child was the difference between the highest digit that he picked and the lowest digit that he picked 8, and this child picked his least digit in the first round.No one picked the same digit as D in any round and D and E did not pick consecutive digits in any round.Question No. 8DIRECTIONS for questions 8 to 10: Select the correct alternative from the given choices.Who picked the least digit in the fourth round? A  C  E

Question

DIRECTIONS for questions 6 to 10: Answer these questions on the basis of the information given below.Five children – A through E – were playing a game. In each round of the game, each child independently picked a digit from 0 to 9 and after each of the five children had picked a digit, the five digits were used to form the largest possible number that can be made with the five digits (by placing them next to each other). This number is labelled as the Ceiling Number of that round. After exactly four rounds, the child who picked the leftmost digit of the highest Ceiling Number across the four rounds is declared the winner of the game. No child can pick the same number across any two rounds.The Ceiling Number of each round are 98551, 75311, 98765 and 76544, not necessarily in any particular order.It is also known thatB picked consecutive digits across the four rounds, but not necessarily in any order, and in none of the rounds did the digit that he picked become the leftmost digit of the Ceiling Number.In each round, the digit that B picked was higher than the one that D picked, while, in the second round, C and E picked the same digit.The child who was declared the winner picked the least digit of the Ceiling Number in only one round, which was the third round.For only one child was the difference between the highest digit that he picked and the lowest digit that he picked 8, and this child picked his least digit in the first round.No one picked the same digit as D in any round and D and E did not pick consecutive digits in any round.Question No. 8DIRECTIONS for questions 8 to 10: Select the correct alternative from the given choices.Who picked the least digit in the fourth round? A  C  E

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Solution

The least digit in the fourth round is 4. From the information given, we know that the child who was declared the winner picked the least digit in only one round, which was the third round. Therefore, the winner did not pick the least digit in the fourth round.

We also know that B picked consecutive digits across the four rounds, but in none of the rounds did the digit that he picked become the leftmost digit of the Ceiling Number. Since 4 is the leftmost digit in the fourth round, B did not pick 4.

We also know that in each round, the digit that B picked was higher than the one that D picked. Since B did not pick 4, D also did not pick 4.

Finally, we know that no one picked the same digit as D in any round and D and E did not pick consecutive digits in any round. Since D did not pick 4, E also did not pick 4.

Therefore, by process of elimination, the only child left who could have picked the least digit in the fourth round is C. So, the answer is C.

This problem has been solved

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