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Mark is getting a piñata for his birthday party. The 4 children at the party are going to take turns trying to break it open. If each child gets one turn, in how many different orders could the children take turns?

Question

Mark is getting a piñata for his birthday party. The 4 children at the party are going to take turns trying to break it open. If each child gets one turn, in how many different orders could the children take turns?

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Solution

The number of different orders in which the children can take turns is determined by the number of permutations of 4 distinct items, which is 4!.

Here's how you calculate it:

  1. Start with the number of children, which is 4.
  2. For the first turn, any of the 4 children could go, so there are 4 possibilities.
  3. For the second turn, only 3 children are left, so there are 3 possibilities.
  4. For the third turn, only 2 children are left, so there are 2 possibilities.
  5. For the fourth turn, only 1 child is left, so there is 1 possibility.

Multiply these possibilities together to get the total number of orders: 4 * 3 * 2 * 1 = 24.

So, there are 24 different orders in which the children could take turns to break open the piñata.

This problem has been solved

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