Statement-I :- Mirror image of optically active will be optically active.Statement-II :- Configuration of mirror image of R-2-Chlorobutane will be S-2-Chlorobutane
Question
Statement-I :- Mirror image of optically active will be optically active.Statement-II :- Configuration of mirror image of R-2-Chlorobutane will be S-2-Chlorobutane
Solution
Statement-I: Yes, the mirror image of an optically active molecule will also be optically active. This is because optical activity is a property of molecules that have a non-superimposable mirror image, also known as chiral molecules. When a molecule is optically active, it means it can rotate plane-polarized light. When you create a mirror image of this molecule, the mirror image will also be able to rotate plane-polarized light, but in the opposite direction. Therefore, the mirror image is also optically active.
Statement-II: Yes, the configuration of the mirror image of R-2-Chlorobutane will be S-2-Chlorobutane. The R/S system is a way to name the absolute configuration of a chiral center. "R" comes from the Latin word "rectus" for right, and "S" from "sinister" for left. If a molecule has an R configuration, its mirror image will have an S configuration, and vice versa. Therefore, if you have a molecule of R-2-Chlorobutane and create its mirror image, the mirror image will have an S configuration.
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