Which is correct statement-If there is chiral carbon then it is optically active.If there is no plane of symmetry then compound will be optically active.In Fischer projection, vertical line represents group towards observer2-Chlorobutane shows optical isomerism
Question
Which is correct statement-If there is chiral carbon then it is optically active.If there is no plane of symmetry then compound will be optically active.In Fischer projection, vertical line represents group towards observer2-Chlorobutane shows optical isomerism
Solution
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"If there is a chiral carbon then it is optically active." - This statement is generally correct. A chiral carbon atom, also known as an asymmetric carbon atom, is a carbon atom that is attached to four different types of atoms or groups of atoms. This leads to molecules that cannot be superimposed on their mirror images, making them optically active.
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"If there is no plane of symmetry then the compound will be optically active." - This statement is also generally correct. A molecule that lacks a plane of symmetry, also known as a chiral molecule, is optically active because it can exist in two non-superimposable forms, known as enantiomers.
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"In Fischer projection, the vertical line represents the group towards the observer." - This statement is incorrect. In Fischer projections, horizontal lines represent bonds that project out from the plane of the paper (towards the observer), while vertical lines represent bonds that extend behind the plane of the paper (away from the observer).
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"2-Chlorobutane shows optical isomerism." - This statement is correct. 2-Chlorobutane has a chiral carbon (the second carbon atom), and thus it exists as two enantiomers, making it optically active.
Similar Questions
Statement-I : Essential condition for a compound to be an optically active is presence of chiral carbon.Statement-II : If there is one chiral carbon then molecule have no symmetry.
Statement–I : the following compound is optically inactive Statement–II : It has two chiral carbons
Assertion :- Compound of which mirror image is non superimposable, is called optically active.Reason :- Condition for a compound to be an optically active is that there should be chiral carbon
Statement-I :- Mirror image of optically active will be optically active.Statement-II :- Configuration of mirror image of R-2-Chlorobutane will be S-2-Chlorobutane
Which of the following statements about chirality and optical isomerism is NOT true:Group of answer choicesA racemic mixture has no optical rotation due to the equal amounts of the two enantiomers cancelling each other out.The necessary condition for an object to be chiral is that it is different from its mirror image.Enantiomers are objects which are non identical mirror images.Enantiomeric molecules differ from one another in the direction which they rotate the plane of polarised light.3-bromopentane is a chiral molecule.
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