A uniform metre scale of length 1m is balanced on a fixed semi–circular cylinder of radius 30 cm as shown in figure. One end of the scale is slightly depressed and released. The time period (in seconds) of the resulting simple harmonic motion is (Take

A particle executes simple harmonicmotion with an amplitude of 5 cm.When the particle is at 4 cm from themean position, the magnitude of itsvelocity in SI units is equal to that of itsacceleration. Then, its periodic time inseconds is

Em um objeto sujeito a um movimento harmônico simples leva 0,25s para ir de um ponto de velocidade zero até o próximo ponto onde isto ocorre. A distância entre estes pontos e de 36 cm. Calcule o período, a frequência e a amplitude do movimento.Assinale a alternativa correta: A 0,5s, 2,0 Hz e 18 cm B 0,6s, 10 Hz e 15 cm C 0,2s, 4,0 Hz e 8 cm D 0,8s, 8,0 Hz e 21 cm

The length of a simple pendulum executing simple harmonic motion is increased by 21%. The percentage increase in the time period of the pendulum of increased length is

The time period of simple harmonic motion depends upon(a) amplitude (b) energy (c) phase constant (d) mass

What is the period of a simple pendulum that is 1.13-m long in each situation?  In the physics lab