What will be the output of the following Python code?x = ['xy', 'za']for i in x: i.swapcase()print(x)
Question
What will be the output of the following Python code?x = ['xy', 'za']for i in x: i.swapcase()print(x)
Solution
The output of the code will be ['xy', 'za'].
Here's the step by step explanation:
-
The list
xis defined with two string elements: 'xy' and 'za'. -
A for loop is initiated to iterate over each element in the list
x. -
Inside the loop, the
swapcase()method is called on the stringi. This method returns a string where all the upper case letters are lower case and vice versa. However, in this case, the result ofi.swapcase()is not stored or used to update the list. -
After the loop, the original list
xis printed. Since no changes were made to the list in the loop, the output will be the original list: ['xy', 'za'].
If you want to update the list with the swapped case strings, you should use a loop that updates the list elements, like this:
x = ['xy', 'za']
for i in range(len(x)):
x[i] = x[i].swapcase()
print(x)
This code would output: ['XY', 'ZA'].
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