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The first, second, and last terms of an Arithmetic Progression(AP) are 37, 370 and 1369 respectively. Then n, the number of terms of the AP is equal toQuestion 1Select one:n= 8.n= 5.n= 8.n= 13.n= 12.

Question

The first, second, and last terms of an Arithmetic Progression(AP) are 37, 370 and 1369 respectively. Then n, the number of terms of the AP is equal toQuestion 1Select one:n= 8.n= 5.n= 8.n= 13.n= 12.

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Solution

In an Arithmetic Progression (AP), the difference between any two successive terms is constant. This difference is called the common difference.

Given that the first term (a) is 37 and the second term is 370, we can find the common difference (d) as follows:

d = 370 - 37 = 333

The nth term of an AP can be found using the formula:

a_n = a + (n-1)d

Where: a_n is the nth term (which is 1369 in this case), a is the first term, n is the number of terms, d is the common difference.

Substituting the given values into the formula, we get:

1369 = 37 + (n-1)333

Solving for n:

(1369 - 37) / 333 + 1 = n

n = 4 + 1 = 5

So, the number of terms in the AP is 5.

This problem has been solved

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