How many terms are there in the arithmetic sequence whose first term and last term are 7 and 43, respectively, and whose common difference is 3?*1 point10111213
Question
How many terms are there in the arithmetic sequence whose first term and last term are 7 and 43, respectively, and whose common difference is 3?*1 point10111213
Solution
To find the number of terms in an arithmetic sequence, you can use the formula:
n = [(l - a) / d] + 1
where: n = number of terms l = last term a = first term d = common difference
In this case, the first term (a) is 7, the last term (l) is 43, and the common difference (d) is 3.
Substituting these values into the formula gives:
n = [(43 - 7) / 3] + 1 n = [36 / 3] + 1 n = 12 + 1 n = 13
So, there are 13 terms in the arithmetic sequence.
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