Consider the growth of S. cerevisiae under aerobic condition in a bioreactor andthe specific growth rate of yeast is 0.5 h-1. The overall reaction of the process is2C6H12O6 +0.2NH3+10.35O2  CH1.8O0.5N0.2+0.2C2H6O+10.6CO2+10.8H2OThe heat of combustion values for different compounds are tabulated below withthe reference to CO2, H2O, O2, and N2 at standard conditions.Compound Heat of combustion(kJ mol-1)C6H12O6 2802NH3 383CH1.8O0.5N0.2 560C2H6O 1366The specific rate of heat production (rounded off to nearest integer) is_____________ kJ mol-1 h-1.

To answer this question, we need to calculate the heat of reaction for the given process and then multiply it by the specific growth rate of the yeast.

Step 1: Calculate the heat of reaction The heat of reaction is the difference between the heat of combustion of the reactants and the products.

For the reactants, we have: 2 moles of C6H12O6: 2 * 2802 kJ/mol = 5604 kJ 0.2 moles of NH3: 0.2 * 383 kJ/mol = 76.6 kJ 10.35 moles of O2: This is our reference, so it contributes 0 kJ.

Adding these up, the total heat of combustion for the reactants is 5604 + 76.6 = 5680.6 kJ.

For the products, we have: 1 mole of CH1.8O0.5N0.2: 1 * 560 kJ/mol = 560 kJ 0.2 moles of C2H6O: 0.2 * 1366 kJ/mol = 273.2 kJ 10.6 moles of CO2: This is our reference, so it contributes 0 kJ. 10.8 moles of H2O: This is our reference, so it contributes 0 kJ.

Adding these up, the total heat of combustion for the products is 560 + 273.2 = 833.2 kJ.

The heat of reaction is then the heat of the reactants minus the heat of the products: 5680.6 kJ - 833.2 kJ = 4847.4 kJ.

Step 2: Multiply by the specific growth rate The specific rate of heat production is the heat of reaction multiplied by the specific growth rate of the yeast: 4847.4 kJ * 0.5 h^-1 = 2423.7 kJ h^-1.

Rounding to the nearest integer, the specific rate of heat production is 2424 kJ mol^-1 h^-1.