On complete combustion of 0.492 g0.492 g of an organic compound containing C,HC,H and O,0.7938 gO,0.7938 g of CO2CO2 and 0.4428 g0.4428 g of H2OH2O was produced. The %% composition of oxygen in the compound is____. (Nearest Integer)
Question
On complete combustion of 0.492 g0.492 g of an organic compound containing C,HC,H and O,0.7938 gO,0.7938 g of CO2CO2 and 0.4428 g0.4428 g of H2OH2O was produced. The %% composition of oxygen in the compound is____. (Nearest Integer)
Solution
To solve this problem, we need to follow these steps:
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First, we need to find out the amount of C and H in the compound from the given data. We know that in CO2, C is 12/44 part by mass and in H2O, H is 2/18 part by mass.
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So, the amount of C in 0.7938 g of CO2 = (12/44) * 0.7938 = 0.216 g And, the amount of H in 0.4428 g of H2O = (2/18) * 0.4428 = 0.0492 g
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The total mass of the compound is given as 0.492 g. So, the amount of O in the compound = Total mass - (mass of C + mass of H) = 0.492 - (0.216 + 0.0492) = 0.2268 g
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Now, we can find the percentage composition of O in the compound = (mass of O / total mass) * 100 = (0.2268 / 0.492) * 100 = 46.1 %
So, the percentage composition of oxygen in the compound is approximately 46% (rounded to the nearest integer).
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