The equation given is already in the standard form for a circle. The standard form for a circle's equation is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

In the equation x² + y² - 49 = 0, we can rewrite it as x² + y² = 49. Here, the center of the circle is at the origin (0,0) and the radius is √49 = 7.

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The equation given is already in the standard form for a circle. The standard form for a circle's equation is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

In the equation x² + y² - 49 = 0, we can rewrite it as x² + y² = 49. Here, the center of the circle is at the origin (0,0) and the radius is √49 = 7.

Knowee AI · Accepted Answer

The equation given is already in the standard form for a circle. The standard form for a circle's equation is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

In the equation x² + y² - 49 = 0, we can rewrite it as x² + y² = 49. Here, the center of the circle is at the origin (0,0) and the radius is √49 = 7.

Write the equation in standard form for the circle x2+y2–49=0.Submit

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