The equation given is already in the standard form for a circle. The standard form for a circle's equation is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

In the equation x² + y² - 1 = 0, we can rewrite it as x² + y² = 1. Here, the center of the circle is at the origin (0,0) and the radius is 1 (since square root of 1 is 1).

Question

The equation given is already in the standard form for a circle. The standard form for a circle's equation is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

In the equation x² + y² - 1 = 0, we can rewrite it as x² + y² = 1. Here, the center of the circle is at the origin (0,0) and the radius is 1 (since square root of 1 is 1).

Knowee AI · Accepted Answer

The equation given is already in the standard form for a circle. The standard form for a circle's equation is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

In the equation x² + y² - 1 = 0, we can rewrite it as x² + y² = 1. Here, the center of the circle is at the origin (0,0) and the radius is 1 (since square root of 1 is 1).

Write the equation in standard form for the circle x2+y2–1=0.Submit

Question

Solution

Similar Questions

Upgrade your grade with Knowee