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Which of the following statements for overloaded operators is true?Select one:a.It is possible to change the precedence of operatorsb.New operators such as **, <> or &/ can be createdc.The overloads of operators && and || lose their short-circuit evaluationd.&&, ||, and , (comma) maintain their special sequencing properties when overloaded

Question

Which of the following statements for overloaded operators is true?Select one:a.It is possible to change the precedence of operatorsb.New operators such as **, <> or &/ can be createdc.The overloads of operators && and || lose their short-circuit evaluationd.&&, ||, and , (comma) maintain their special sequencing properties when overloaded

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Solution

The correct answer is c. The overloads of operators && and || lose their short-circuit evaluation.

Here's why:

a. It is not possible to change the precedence of operators. The precedence of operators is determined by the language's syntax and cannot be altered.

b. You cannot create new operators. The set of operators is fixed in the language.

c. When you overload the && and || operators, they lose their short-circuit evaluation. In other words, both sides of the operation are evaluated regardless of the result of the first operand, which is not the case with the built-in versions of these operators.

d. The &&, ||, and , (comma) operators do not maintain their special sequencing properties when overloaded. These properties are specific to the built-in versions of the operators.

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