public abstract class Shape { private int x; private int y; public abstract void draw(); public void setAnchor(int x, int y) { this.x = x; this.y = y; }} Which two classes use the Shape class correctly? (Choose two.)Select one or more:a.public abstract class Circle extends Shape { private int radius;}b.public class Circle extends Shape { private int radius; public void draw();}c.public class Circle extends Shape { private int radius; public void draw() {/* code here */}}d.public class Circle implements Shape { private int radius;}
Question
public abstract class Shape { private int x; private int y; public abstract void draw(); public void setAnchor(int x, int y) { this.x = x; this.y = y; }} Which two classes use the Shape class correctly? (Choose two.)Select one or more:a.public abstract class Circle extends Shape { private int radius;}b.public class Circle extends Shape { private int radius; public void draw();}c.public class Circle extends Shape { private int radius; public void draw() {/* code here */}}d.public class Circle implements Shape { private int radius;}
Solution
The correct answers are:
a. public abstract class Circle extends Shape { private int radius;}
c. public class Circle extends Shape { private int radius; public void draw() {/* code here */}}
Explanation:
Option a is correct because an abstract class can extend another abstract class. It doesn't need to provide an implementation for the abstract method in the parent class.
Option c is correct because it's a concrete class extending an abstract class and providing an implementation for the abstract method 'draw()'.
Option b is incorrect because it declares the method 'draw()' without providing an implementation. This would be fine if 'Circle' was declared as an abstract class, but it's not.
Option d is incorrect because 'Circle' is declared to implement 'Shape', but 'Shape' is a class, not an interface. In Java, a class can extend another class, but it can only implement an interface.
Similar Questions
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