Three capacitors: 3.0 μF, 5.0 μF and 7.0 μF are connected in series and in parallel. The equivalent capacitance in series and parallel are ……….*1 point0.15 μF and 15 μF1.5 μF and 15 μF15 μF and 1.5 μF15 μF and 0.15 μF
Question
Three capacitors: 3.0 μF, 5.0 μF and 7.0 μF are connected in series and in parallel. The equivalent capacitance in series and parallel are ……….*1 point0.15 μF and 15 μF1.5 μF and 15 μF15 μF and 1.5 μF15 μF and 0.15 μF
Solution
The equivalent capacitance for capacitors in series (Cs) is given by the reciprocal of the sum of the reciprocals of the individual capacitances.
So, 1/Cs = 1/C1 + 1/C2 + 1/C3 = 1/3 + 1/5 + 1/7 = 0.333 + 0.2 + 0.143 = 0.676
Therefore, Cs = 1 / 0.676 = 1.48 μF, which is approximately 1.5 μF.
The equivalent capacitance for capacitors in parallel (Cp) is given by the sum of the individual capacitances.
So, Cp = C1 + C2 + C3 = 3 + 5 + 7 = 15 μF
Therefore, the equivalent capacitance in series and parallel are 1.5 μF and 15 μF respectively.
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