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What is the total capacitance of three capacitors connected in parallel with values of 2.2 μF, 6 μF and 3.2 μF?

Question

What is the total capacitance of three capacitors connected in parallel with values of 2.2 μF, 6 μF and 3.2 μF?

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Solution

When capacitors are connected in parallel, the total capacitance (C_total) is simply the sum of the individual capacitances.

Here are the steps to calculate the total capacitance:

  1. Identify the capacitance of each capacitor. In this case, the capacitors have capacitances of 2.2 μF, 6 μF, and 3.2 μF.

  2. Add the capacitances together to calculate the total capacitance.

C_total = C1 + C2 + C3 C_total = 2.2 μF + 6 μF + 3.2 μF C_total = 11.4 μF

Therefore, the total capacitance of the three capacitors connected in parallel is 11.4 μF.

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