This exercise is to test your understanding of Java Strings. A sample String declaration:String myString = "Hello World!"The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.Given two strings of lowercase English letters, and , perform the following operations:Sum the lengths of and .Determine if is lexicographically larger than (i.e.: does come before in the dictionary?).Capitalize the first letter in and and print them on a single line, separated by a space.Input FormatThe first line contains a string . The second line contains another string . The strings are comprised of only lowercase English letters.Output FormatThere are three lines of output:For the first line, sum the lengths of and .For the second line, write Yes if is lexicographically greater than otherwise print No instead.For the third line, capitalize the first letter in both and and print them on a single line, separated by a space.Sample Input 0hellojavaSample Output 09NoHello JavaExplanation 0String is "hello" and is "java". has a length of , and has a length of ; the sum of their lengths is .When sorted alphabetically/lexicographically, "hello" precedes "java"; therefore, is not greater than and the answer is No.When you capitalize the first letter of both and and then print them separated by a space, you get "Hello Java".

Here is a step-by-step solution in Java:

1. First, we need to read the input strings. We can use the Scanner class in Java to do this.

Scanner sc=new Scanner(System.in);
String A=sc.next();
String B=sc.next();

2. Next, we need to find the sum of the lengths of the two strings. We can use the length() method of the String class to do this.

int sum = A.length() + B.length();
System.out.println(sum);

3. To determine if string A is lexicographically larger than string B, we can use the compareTo() method of the String class. If A is lexicographically larger than B, compareTo() will return a positive number.

System.out.println(A.compareTo(B) > 0 ? "Yes" : "No");

4. Finally, to capitalize the first letter of both strings and print them on a single line, separated by a space, we can use the substring() method of the String class to separate the first character from the rest of the string, and then use the toUpperCase() method to capitalize the first character.

System.out.println(A.substring(0, 1).toUpperCase() + A.substring(1) + " " + B.substring(0, 1).toUpperCase() + B.substring(1));

So, the complete code will look like this:

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        String A=sc.next();
        String B=sc.next();
        int sum = A.length() + B.length();
        System.out.println(sum);
        System.out.println(A.compareTo(B) > 0 ? "Yes" : "No");
        System.out.println(A.substring(0, 1).toUpperCase() + A.substring(1) + " " + B.substring(0, 1).toUpperCase() + B.substring(1));
    }
}