What will be the output of the program?String x = "xyz";x.toUpperCase(); /* Line 2 */String y = x.replace('Y', 'y');y = y + "abc";System.out.println(y);abcXyZabcxyzxyzabcXyZabc
Question
What will be the output of the program?String x = "xyz";x.toUpperCase(); /* Line 2 */String y = x.replace('Y', 'y');y = y + "abc";System.out.println(y);abcXyZabcxyzxyzabcXyZabc
Solution
The output of the program will be "xyzabc". Here's why:
-
The program starts by creating a String variable
xand assigning it the value "xyz". -
The next line
x.toUpperCase();converts the string to uppercase. However, the result of this operation is not stored anywhere, so it has no effect on the program. -
The program then creates another String variable
yand assigns it the value ofxwith all occurrences of 'Y' replaced with 'y'. Sincexis "xyz" and there is no 'Y' in it,yis also "xyz". -
The next line
y = y + "abc";appends "abc" toy, soybecomes "xyzabc". -
Finally, the program prints out the value of
y, which is "xyzabc".
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