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An inductor with inductance L is connected to an AC power source having a peak value of 37.5 V and f = 911 Hz. If the reactance of the inductor is supposed to be 239.83 Ω, what value of L is needed?  mH

Question

An inductor with inductance L is connected to an AC power source having a peak value of 37.5 V and f = 911 Hz. If the reactance of the inductor is supposed to be 239.83 Ω, what value of L is needed?  mH

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Solution

The reactance (X) of an inductor can be calculated using the formula:

X = 2πfL

where:

  • X is the reactance (in ohms, Ω)
  • f is the frequency (in hertz, Hz)
  • L is the inductance (in henries, H)

We can rearrange this formula to solve for L:

L = X / (2πf)

Substituting the given values:

L = 239.83 Ω / (2π * 911 Hz)

This will give you the inductance in henries. To convert this to millihenries (mH), you multiply by 1000 (since 1 H = 1000 mH).

So, the final calculation is:

L = (239.83 Ω / (2π * 911 Hz)) * 1000 mH

Now you can calculate the value of L.

This problem has been solved

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