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The distance between places A and B is 999 km. An express train leaves place A at 6 am and runs at a speed of 55.5 km/hr. The train stops on the way for 1 hours 20 minutes. It reaches B at?

Question

The distance between places A and B is 999 km. An express train leaves place A at 6 am and runs at a speed of 55.5 km/hr. The train stops on the way for 1 hours 20 minutes. It reaches B at?

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Solution

To solve this problem, we need to find out how long the train journey takes, including the time it stops.

  1. First, we calculate the time it takes for the train to travel from A to B without stopping. We do this by dividing the total distance by the speed of the train. So, 999 km ÷ 55.5 km/hr = 18 hours.

  2. Then, we add the time the train stops on the way, which is 1 hour and 20 minutes. To add this to our previous result, we need to convert 20 minutes to hours by dividing by 60. So, 20 ÷ 60 = 0.33 hours. Therefore, 1 hour and 20 minutes is approximately 1.33 hours.

  3. We add this to the 18 hours we calculated earlier. So, 18 hours + 1.33 hours = 19.33 hours.

  4. The train leaves at 6 am. To find out when it arrives at B, we add the total time of the journey to the departure time. However, since our result is in decimal hours, we need to convert it back to hours and minutes. We do this by taking the decimal part (0.33) and multiplying it by 60 to get minutes. So, 0.33 x 60 = 20 minutes.

  5. Therefore, the train arrives at B at 6 am + 19 hours and 20 minutes = 1:20 am the next day.

This problem has been solved

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