A and B start from the same point and cover equal distances. A travels by car and covers the distance in 3 hours with a speed of 50 kmph. B travels by a bus which stops for 10 minutes after covering 10 km. In how much time will the bus reach the destination, if the speed of the bus is 40% less than the car?
Question
A and B start from the same point and cover equal distances. A travels by car and covers the distance in 3 hours with a speed of 50 kmph. B travels by a bus which stops for 10 minutes after covering 10 km. In how much time will the bus reach the destination, if the speed of the bus is 40% less than the car?
Solution
Step 1: Calculate the total distance covered by A. A travels at a speed of 50 kmph for 3 hours. So, the total distance covered by A = speed * time = 50 kmph * 3 hours = 150 km.
Step 2: Determine the speed of the bus. The speed of the bus is 40% less than the car. So, the speed of the bus = 50 kmph - (40/100 * 50 kmph) = 30 kmph.
Step 3: Calculate the time taken by the bus to cover 10 km. Time = Distance / Speed = 10 km / 30 kmph = 1/3 hour = 20 minutes.
Step 4: Calculate the total time taken by the bus to cover 10 km including the stoppage time. Total time = Time taken to cover 10 km + stoppage time = 20 minutes + 10 minutes = 30 minutes.
Step 5: Calculate the total time taken by the bus to cover the entire distance. Since the bus covers 10 km in 30 minutes, it will cover 150 km in (150 km / 10 km) * 30 minutes = 450 minutes = 7.5 hours.
So, the bus will reach the destination in 7.5 hours.
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