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An expression is shown below:2x3y + 8xy − 4x2y − 16yPart A: Rewrite the expression by factoring out the greatest common factor. (4 points)Part B: Factor the entire expression completely. Show the steps of your work. (6 points)

Question

An expression is shown below:2x3y + 8xy − 4x2y − 16yPart A: Rewrite the expression by factoring out the greatest common factor. (4 points)Part B: Factor the entire expression completely. Show the steps of your work. (6 points)

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Solution

Part A: Rewrite the expression by factoring out the greatest common factor.

Given expression: 2x3y+8xy4x2y16y2x^3y + 8xy - 4x^2y - 16y

Step 1: Identify the greatest common factor (GCF) of all the terms.

  • The GCF of the coefficients (2, 8, -4, -16) is 2.
  • The GCF of the variable parts (considering xx and yy) is yy.

Step 2: Factor out the GCF from each term.

  • The GCF of the entire expression is 2y2y.

So, the expression can be rewritten as: 2y(x3+4x2x28)2y(x^3 + 4x - 2x^2 - 8)

Part B: Factor the entire expression completely.

Step 1: Simplify the expression inside the parentheses. 2y(x3+4x2x28)2y(x^3 + 4x - 2x^2 - 8)

Step 2: Rearrange the terms inside the parentheses to make it easier to factor by grouping. 2y(x32x2+4x8)2y(x^3 - 2x^2 + 4x - 8)

Step 3: Factor by grouping. Group the terms in pairs: 2y[(x32x2)+(4x8)]2y[(x^3 - 2x^2) + (4x - 8)]

Step 4: Factor out the common factors from each group. 2y[x2(x2)+4(x2)]2y[x^2(x - 2) + 4(x - 2)]

Step 5: Notice that (x2)(x - 2) is a common factor in both groups. 2y[(x2)(x2+4)]2y[(x - 2)(x^2 + 4)]

So, the completely factored expression is: 2y(x2)(x2+4)2y(x - 2)(x^2 + 4)

This problem has been solved

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