Fully factorise this expression: 2𝑥𝑦4−𝑦22xy 4 −y 2
Question
Fully factorise this expression: 2𝑥𝑦4−𝑦22xy 4 −y 2
Solution
The expression you provided seems to have a typo. I believe it should be 2x^2y^4 - y^2.
Here are the steps to factorize the expression:
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Identify the common factors in both terms. In this case, the common factor is y^2.
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Factor out the common factor from each term. This gives us: y^2(2x^2y^2 - 1)
So, the factorized form of the expression 2x^2y^4 - y^2 is y^2(2x^2y^2 - 1).
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