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Fully factorise this expression: 2𝑥𝑦4−𝑦22xy 4 −y 2

Question

Fully factorise this expression: 2𝑥𝑦4−𝑦22xy 4 −y 2

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Solution

The expression you provided seems to have a typo. I believe it should be 2x^2y^4 - y^2.

Here are the steps to factorize the expression:

  1. Identify the common factors in both terms. In this case, the common factor is y^2.

  2. Factor out the common factor from each term. This gives us: y^2(2x^2y^2 - 1)

So, the factorized form of the expression 2x^2y^4 - y^2 is y^2(2x^2y^2 - 1).

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