A circuit is constructed from two voltage sources (V1 and V2) and three resistors (R1, R2, and R3).If the potential of each voltage source is 10 V and the resistance of each resistor is 5 Ω, what is the current exiting Point A into R3?A.0.7 C/sB.1.0 C/sC.1.3 C/sD.1.6 C/s

To solve this problem, we need to know the configuration of the circuit, which is not provided in the question. The resistors could be in series or parallel, and the voltage sources could be in series or parallel as well.

However, if we assume that the resistors are in series and the voltage sources are in parallel (which is a common configuration), we can use Ohm's law (V = IR) to find the current.

In this case, the total voltage would be 10V (since the voltage sources are in parallel, the total voltage is the same as each individual voltage source). The total resistance would be the sum of all the resistors, which is 5Ω + 5Ω + 5Ω = 15Ω.

So, the current I would be V/R = 10V / 15Ω = 0.67 C/s.

However, this option is not available in the choices. Therefore, we need more information about the configuration of the circuit to solve this problem accurately.