Ver en españolWrite the equation in standard form for the circle x2+y2–6x+5=0.Submit
Question
Ver en españolWrite the equation in standard form for the circle x2+y2–6x+5=0.Submit
Solution
The equation of a circle in standard form is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.
The given equation is x² + y² - 6x + 5 = 0.
To convert this into standard form, we need to complete the square for the x terms.
First, rearrange the equation to group the x terms together:
x² - 6x + y² = -5
Next, take half of the coefficient of x, square it, and add it to both sides of the equation. Half of -6 is -3, and (-3)² = 9.
(x² - 6x + 9) + y² = -5 + 9
This simplifies to:
(x - 3)² + y² = 4
So, the equation of the circle in standard form is (x - 3)² + y² = 4. The center of the circle is (3,0) and the radius is 2 (since √4 = 2).
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