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Ver en españolWrite the equation in standard form for the circle x2+y2–6x+5=0.Submit

Question

Ver en españolWrite the equation in standard form for the circle x2+y2–6x+5=0.Submit

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Solution

The equation of a circle in standard form is (x-h)² + (y-k)² = r², where (h,k) is the center of the circle and r is the radius.

The given equation is x² + y² - 6x + 5 = 0.

To convert this into standard form, we need to complete the square for the x terms.

First, rearrange the equation to group the x terms together:

x² - 6x + y² = -5

Next, take half of the coefficient of x, square it, and add it to both sides of the equation. Half of -6 is -3, and (-3)² = 9.

(x² - 6x + 9) + y² = -5 + 9

This simplifies to:

(x - 3)² + y² = 4

So, the equation of the circle in standard form is (x - 3)² + y² = 4. The center of the circle is (3,0) and the radius is 2 (since √4 = 2).

This problem has been solved

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