Knowee
Questions
Features
Study Tools

Inoculation is the start of the process. Initially the bacterial population at the time of experiment was 10,000. The number of bacterias in the lag phase increases by the following formula, . Here,  is the initial number of bacterias and  is the number of bacterias in Lag Phase. Also, the number of bacteria in the stationary phase remains the same. In the exponential phase, the bacterias grow according to the following formula,   Here,  is the time for which the exponential phase lasts. Similarly, the death/decline phase follows the following formula, Here,  is the number of bacterias in the stationary phase and  is the time for which death/decline phase lasts.  The table below represents the time period for which a certain phase lasted.  Time (in hours) Phase0 - 1.5 Lag Phase1.5 - 3.5 Exponential Phase3.5 - 12 Stationary PhaseAfter 12 hours Decline/Death Phase Q 4.1A 4Write down in the blanks proper values so that they satisfy the statements. [Do not put any commas or full stops in the values] The number of bacterias from (0 - 1.5) hours of the experiment is .The number of bacterias at the end of 3.5 hours are .The number of bacterias in the stationary phase are .The number of bacterias after 20 hours of the start of the experiment after rounding off are

Question

Inoculation is the start of the process. Initially the bacterial population at the time of experiment was 10,000. The number of bacterias in the lag phase increases by the following formula, . Here,  is the initial number of bacterias and  is the number of bacterias in Lag Phase. Also, the number of bacteria in the stationary phase remains the same. In the exponential phase, the bacterias grow according to the following formula,   Here,  is the time for which the exponential phase lasts. Similarly, the death/decline phase follows the following formula, Here,  is the number of bacterias in the stationary phase and  is the time for which death/decline phase lasts.  The table below represents the time period for which a certain phase lasted.  Time (in hours) Phase0 - 1.5 Lag Phase1.5 - 3.5 Exponential Phase3.5 - 12 Stationary PhaseAfter 12 hours Decline/Death Phase Q 4.1A 4Write down in the blanks proper values so that they satisfy the statements. [Do not put any commas or full stops in the values] The number of bacterias from (0 - 1.5) hours of the experiment is .The number of bacterias at the end of 3.5 hours are .The number of bacterias in the stationary phase are .The number of bacterias after 20 hours of the start of the experiment after rounding off are

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

I'm sorry, but your question seems to be incomplete. The formulas for the bacterial growth in different phases are not provided. Could you please provide the formulas so I can help you calculate the number of bacteria at different stages?

Similar Questions

A bacterial strain is growing exponentially. At 10:00 am the titre of the culture is 4 x 106 cells per ml. At 4 pm, the culture is still growing exponentially and the titre has increased to 6 x 108 cells per ml. Assuming that the bacterial strain was in exponential phase growth prior to the measurements at 10:00 am, how many generations would have elapsed between 08:00 am and 4pm? Show all of your calculations. This culture will eventually reach the death phase when the nutrients become limited. What does happen in this phase? What strategies do bacteria develop to cope with nutrient shortages?

The phase of the bacterial growth curve that shows the maximum rate of cell division is the A. lag phase. B. exponential (log) phase. C. stationary phase. D. death phase. E. prophase.

Exactly 200 bacteria are inoculated into fresh sterile growth medium at 9am and maintained at an optimum incubation temperature throughout the day. If the bacteria had a generation time of 30 minutes and there was a 1 hour lag period, how many generations will then take place by 3pm? The growth of the bacterium in log phase can be expressed by the following equations: Nt = N0 2n & g = (T – T0) / n Where n = number of generations, N0 = initial number of cells at a particular time (T0), Nt = final number of cells at a particular time (T), and g = generation time Group of answer choices 8 10 12 20 24

A culture of bacteria has an initial population of 83000 bacteria and doubles every 10 hours. Using the formula P, start subscript, t, end subscript, equals, P, start subscript, 0, end subscript, dot, 2, start superscript, start fraction, t, divided by, d, end fraction, end superscriptP t​ =P 0​ ⋅2 dt​ , where P, start subscript, t, end subscriptP t​ is the population after t hours, P, start subscript, 0, end subscriptP 0​ is the initial population, t is the time in hours and d is the doubling time, what is the population of bacteria in the culture after 3 hours, to the nearest whole number?

The simulation is designed so that individual bacteria live for only three seconds. In that time, they need to eat two pieces of food before they can reproduce. With this information, predict how the population of bacteria might evolve.Over many generations, the average speed of the population will:

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.