Exactly 200 bacteria are inoculated into fresh sterile growth medium at 9am and maintained at an optimum incubation temperature throughout the day. If the bacteria had a generation time of 30 minutes and there was a 1 hour lag period, how many generations will then take place by 3pm? The growth of the bacterium in log phase can be expressed by the following equations: Nt = N0 2n & g = (T – T0) / n Where n = number of generations, N0 = initial number of cells at a particular time (T0), Nt = final number of cells at a particular time (T), and g = generation time Group of answer choices 8 10 12 20 24
Question
Exactly 200 bacteria are inoculated into fresh sterile growth medium at 9am and maintained at an optimum incubation temperature throughout the day. If the bacteria had a generation time of 30 minutes and there was a 1 hour lag period, how many generations will then take place by 3pm?
The growth of the bacterium in log phase can be expressed by the following equations: Nt = N0 2n & g = (T – T0) / n
Where n = number of generations, N0 = initial number of cells at a particular time (T0), Nt = final number of cells at a particular time (T), and g = generation time
Group of answer choices
8
10
12
20
24
Solution
To solve this problem, we first need to determine the total time that the bacteria were actually growing. Given that the bacteria were inoculated at 9am and there was a 1 hour lag period, the bacteria started growing at 10am. If we want to know how many generations took place by 3pm, we have a total of 5 hours of growth (from 10am to 3pm).
Since the generation time of the bacteria is 30 minutes, we can calculate the number of generations by dividing the total growth time by the generation time.
So, 5 hours = 300 minutes.
300 minutes / 30 minutes/generation = 10 generations.
Therefore, the correct answer is 10 generations.
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